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If you were solving a system of equations and you came to a statement like 1 = 3, what do you know about the solution(s) to this system?
Part 2:
Solve the following system and show all of your work.
x − 2y = 14
x + 3y = 9
 2 years ago
 2 years ago
If you were solving a system of equations and you came to a statement like 1 = 3, what do you know about the solution(s) to this system? Part 2: Solve the following system and show all of your work. x − 2y = 14 x + 3y = 9
 2 years ago
 2 years ago

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vishal_kothariBest ResponseYou've already chosen the best response.1
it tells you that there is no solution i.e. if graphing the 2 equations, the lines do NOT cross. ...
 2 years ago

vishal_kothariBest ResponseYou've already chosen the best response.1
x 2y = 14 x+3y = 9 need a common factor to cancel x to to solve for y though the cancelling of terms . 1 is good. So I'll use it x2y = 14 (1) x +3y = 9(1)  Multiplying a negative number to one of the equation to both sides of it to change a variable from a negative value to a positive one or vise verse to cancel one of the terms to solve for the other though the addition of terms x 2y = 14 x3y= 9   Multiplication and addition of terms 0x 5y = 5 5y = 5  Addition 1/5* 5y = 5 * 1/5  Multiplying the reciprocal of a coefficient to both sides of the equation to solve for y y = 5/5  Multiplication y = 1  Division let solve for x x2y = 14  one of the original equations x  2(1) = 14  substituting y with 1 x + 2 = 14  Multiplication x + 2 2 = 14 2  Adding the additive inverse of a number to both sides of the equation to move it to the other side of it x= 12  Addition proof: x 2y = 14 x+3y = 9  original equation 122(1) = 14 12+ 3(1) = 9  substituting y and x with 1, and 12 12+ 2 = 14 123 = 9  Multiplication 14 = 14 9 = 9  Addition ...
 2 years ago

vishal_kothariBest ResponseYou've already chosen the best response.1
i think it helps...
 2 years ago
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