A community for students.
Here's the question you clicked on:
 0 viewing
 2 years ago
what is the current thru the 2ohm resistor in the figure? what power is dissipated by the 2ohm resistor in the figure?
 2 years ago
what is the current thru the 2ohm resistor in the figure? what power is dissipated by the 2ohm resistor in the figure?

This Question is Closed

elica85
 2 years ago
Best ResponseYou've already chosen the best response.0ignore the current direction if it's wrong

suyash011
 2 years ago
Best ResponseYou've already chosen the best response.0dw:1332192864001:dw Now using Kirchoff's Current Law (x15)/4 + (x0)/2 + (x+120)/4 = 0 x15 + 2x + x+12 = 0 4x = 3 x = 3/4 I1 = (150.75)/4 = 14.25/4 = 3.5625 Amperes I2 = 0.375 Amperes I3 = 3.1875 Amperes

elica85
 2 years ago
Best ResponseYou've already chosen the best response.0the loop law is summation of potential difference=0...V=IR so what's the first line of equation?

radar
 2 years ago
Best ResponseYou've already chosen the best response.1Or you could Thevenize it. Mentally remove the 2 Ohm resistor, compute the voltage that would be present in the simple series ckt with the two sources and the two 4 Ohm resistors.dw:1332269821486:dw you will come up with a 1.5 volts. That is the Thevenin voltage. Now mentally short the two sources and look into the circuit (where the 2 Ohms was. You will now see the 2 4 Ohm resistors in parallel giving you the Thevinen resistance of 2 Ohm. This is what you now have:dw:1332270017523:dw Connecting the 2 Ohm resistor back in, you can easily calculate the current through it: 1.5/4=.375 A or 375 ma.

radar
 2 years ago
Best ResponseYou've already chosen the best response.1The power can now be calculated:\[P=i ^{2}R=(.375)^{2}2=.28125 watts\]
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.