anonymous
  • anonymous
Find the limit (if it exists). lim (6x^2 + x − 1) /(6x^2 − 3x − 3) x→(−1/2)+
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
i've tried both + and - infinity, and I know there's an asymptote around 1, but I can't figure it out...
anonymous
  • anonymous
when I see this , first thing I instinctively do is factor 3(x-1)(2x+1)
anonymous
  • anonymous
^ that was denominator

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anonymous
  • anonymous
do you then set the factors equal to zero to find the limits?
anonymous
  • anonymous
x=1 and -1/2?
anonymous
  • anonymous
numerator (2x+1)(3x-1) ---------------- 3(2x+1)(x-1) now cancel out (3x-1) ----------- 3(x-1) now evaluate
anonymous
  • anonymous
how do you evaluate it? by subbing in -1/2? (3*-0.5)-1 / (3(-1.5) =-2.5 / -4.5
anonymous
  • anonymous
=5/9
anonymous
  • anonymous
yes
anonymous
  • anonymous
really? Yess!!
anonymous
  • anonymous
thank you thank you!!
anonymous
  • anonymous
i understand!
anonymous
  • anonymous
I think you did

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