anonymous
  • anonymous
So, i'm confused about the notation for stating the location of vertical asymptotes of this function s(t) = 2t / sin(t)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
i know the asymptotes are located at x=n*pi, but I'm not sure how to express that in this case. Every answer I put is wrong.
anonymous
  • anonymous
so far i've tried x=3, 3pi, 3n, sin(t), -sin(t), and 0
anonymous
  • anonymous
or for that matter @imranmeah91

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anonymous
  • anonymous
for what value of t is denominator 0
anonymous
  • anonymous
you're speedy
anonymous
  • anonymous
0
anonymous
  • anonymous
obiviously , t=0 but that's not all
anonymous
  • anonymous
oh, ok
anonymous
  • anonymous
sine is periodic function sin(0)=0 sin(pi)=0 sin(2pi)=0 you get the drift let n b any integer , n=0,1,2,3,4,5, sin(n pi)=0 so our verticle retricemtote is x= n pi
anonymous
  • anonymous
retricemtote=asymtote stupid autocorrect messed it up
anonymous
  • anonymous
so, does n=anything in particular, or if it true for all n?
anonymous
  • anonymous
**is it true
anonymous
  • anonymous
n has to be integer though
anonymous
  • anonymous
imranmeah91, you are fantastic. It's so neat to be able to come online with all my questions after class and find someone who will make things more clear! I really appreciate it!
anonymous
  • anonymous
you are welcome, great to hear

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