anonymous
  • anonymous
CAN SOMEONE PLEASE HELP ME WITH THIS I ASK LIKE TWICE ALREADY... Observe parallelogram ABCD plotted on the coordinate plane below. Part I: Provide the coordinates of a parallelogram A’B’C’D’ that is congruent to parallelogram ABCD. Explain why these figures are congruent. (4 points) Part II: Provide the coordinates of a parallelogram A’’B’’C’’D’’ that is similar to parallelogram ABCD. Explain why these figures are similar. (6 points)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
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anonymous
  • anonymous
guess this too hard for you guys
across
  • across
I would have loved to help you. :) But then I read your last comment. :/

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anonymous
  • anonymous
so it is then?
across
  • across
Sure. That is way out of my league.
anonymous
  • anonymous
you sarcastic or what, and or you gonna help?
across
  • across
I will only if you ask politely.
anonymous
  • anonymous
may you please help me with this problem ?
across
  • across
Sure I will. You are given a parallelogram \(ABCD\) with the following Cartesian plane coordinates:\[A:(-7,3)\]\[B:(-5,7)\]\[C:(1,7)\]\[D:(-1,3)\]and are asked to provide a parallelogram \(A'B'C'D'\) that is congruent to it. The easiest way to do this is to perform a simple shift (either upward or downward) of your original figure. Let us perform a downward shift of \(1\) unit on it for simplicity:\[A':(-7,2)\]\[B':(-5,6)\]\[C':(1,6)\]\[D':(-1,2)\]Parallelogram \(A'B'C'D'\) is congruent to parallelogram \(ABCD\) because their corresponding sides and angles are equal. Now for the similar figure...
anonymous
  • anonymous
so would the similar be A=(0,0) B=(1,2) C=(4,2) D=(3,0) AM JUST TRYING
across
  • across
Let\[A'':(-14,6)\]\[B'':(-10,14)\]\[C'':(2,14)\]\[D'':(-2,6)\]Then parallelogram \(A''B''C''D''\) is similar to parallelogram \(ABCD\) because their corresponding angles are the same and their sides are in proportion.
anonymous
  • anonymous
oh ok, not really there yet but i kinda see the concept a lil
anonymous
  • anonymous
and thanks :)

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