anonymous
  • anonymous
7u^2-4u-3 cant be factored can it?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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AccessDenied
  • AccessDenied
What would you do to show whether it could be factored?
anonymous
  • anonymous
find factors of -3 that adds up to give you -4
AccessDenied
  • AccessDenied
well, we can't do that since we have that 7 as the leading coefficient. We can only check -3 alone if the leading coefficient is 1 You would instead check for factors of the leading coefficient times the constant that add to -4. 7*(-3)

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kunal
  • kunal
apply quadratic formula...............
anonymous
  • anonymous
Yah what kunal said...
AccessDenied
  • AccessDenied
we do not use quadratic formula for factoring we're looking for factors of -21 that add up to -7.
AccessDenied
  • AccessDenied
er, add up to -4*
anonymous
  • anonymous
okay...
anonymous
  • anonymous
Won't you get (7u-3)(u-1)
AccessDenied
  • AccessDenied
we'd use those factors and rewrite it in the form 7u^2 - Au + Bu - 3 then factor out of the first two terms and the last two terms
anonymous
  • anonymous
Did I do something wrong???
anonymous
  • anonymous
i got (7u-3) (u-1)
AccessDenied
  • AccessDenied
not quite correct... you may not be accounting for a negative somewhere if you multiply it back together, you get 7u^2 - 7u - 3u + 3 which is 7u^2 - 10u + 3
anonymous
  • anonymous
O I know what I did wrong....
anonymous
  • anonymous
okay I see what your saying!
kunal
  • kunal
7u^ - 7u + 4u -3
anonymous
  • anonymous
So will it be (7u+3)(u-1)?
AccessDenied
  • AccessDenied
yes, that would be correct. :)
kunal
  • kunal
yes the answer is 1 and -3/7

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