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area of the sector is A(s) = pi*12^2*75/360 area of the triangle is A(t) = 12^2*(sin75)/2 area of shaded is A(s)-A(t)
this is confusing :/
dpalnc ....how did you arrive at your triangle area...I have something different.
The procedure is correct.
sector minus the triangle is the correct approach.
area of the sector is correct.
i dont understand the area of a sector set up that you wrote
you are taking part of a circle for the sector.
now you have to subtract the triangle to get what is left.
you will need to use law of sines to find the missing sides and angles, then take one half base times height, or use Heron's Formula.
is it 75/360 * area (the other part i cant tell what it is)
for the 75/360 * pie (12)^2 i got 30 pie or 94.2
yep...that is the area of the sector....now you have to find the area of the triangle.
so that is how you do it?
thank you so much for your time and patience i wish i could give you more gold medals!
now you have to find the height
subtract the area of the triangle...one half base time the height. you now have the base, all you need is the height.
wait we have to do all this to find the area of the shaded region?
wow i didnt expect alot
thank you so much :)
if the angles are nice...90 or 60...etc...its easier.
sure, have a good night.
same to you sir/m'am !
if you know two sides of a triangle an the angle between those two sides, the area of the triangle is obtained by the formula side1*side2*sin(75)/2: |dw:1332305035718:dw|
in this problem, s1 = s2 = 12, and the angle between them is 75 degrees. So the area of the triangle is 1/2*12*12*sin75
your welcome :)