anonymous
  • anonymous
Find all of the critical numbers of the function fx=x^3-3x^2 on the open interval (-1,1). (Hint: If there is more than one value, separate the critical numbers with commas.) Answer =
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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amistre64
  • amistre64
what our derivative?
anonymous
  • anonymous
hold on
anonymous
  • anonymous
3x^2-6x

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amistre64
  • amistre64
do we want criticals for mina nd max, or for inflections as well?
anonymous
  • anonymous
just the critical for min and max
amistre64
  • amistre64
then 3x^2-6x=0 will be a good critical points to check for min and max
amistre64
  • amistre64
3x(x-2) = 0 when x=0 and x=2 i beleive
anonymous
  • anonymous
x=2 and x=0 but that is not the correct answer idk why
amistre64
  • amistre64
then our definition of critical points is off
anonymous
  • anonymous
its on the interval (-1,1)
amistre64
  • amistre64
then 0 would be a point of interest
amistre64
  • amistre64
whats our second derivative?
anonymous
  • anonymous
6x-6
amistre64
  • amistre64
http://www.wolframalpha.com/input/?i=x%5E3-3x%5E2+from+x%3D-1+to+1 our graph is this then x=1 looks to be a point of inflection as well
amistre64
  • amistre64
since we have open end points we cant really include them can we?
anonymous
  • anonymous
yes i guess
anonymous
  • anonymous
but there is def. an answer to this
amistre64
  • amistre64
then it appears out critical points is when x=0 ....
amistre64
  • amistre64
all the others are out of our range of interval
anonymous
  • anonymous
i still cant figure out the answer
amistre64
  • amistre64
f(0) = ?
anonymous
  • anonymous
0
amistre64
  • amistre64
i assume this is a program that your inputing an answer into ...
anonymous
  • anonymous
correct
amistre64
  • amistre64
then it might be a good idea to capture a screen shot with the instructions so that we might be able to formulate a "proper" response :)
anonymous
  • anonymous
it works thanks
amistre64
  • amistre64
lol :) youre welcome

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