anonymous
  • anonymous
If it requires 7.0 J of work to stretch a particular spring by 2.3 cm from its equilibrium length, how much more work will be required to stretch it an additional 3.9 cm?
Physics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
Recall that work is defined as\[W = \int\limits F dx\]and that the force of a spring is\[F_s = kx\]Substituting \[W = \int\limits kx dx\]Integrating\[W = {1 \over 2} k x^2\] Therefore, with the given data, we can determine the spring constant. Once we know the spring constant, we can determine the additional work required to stretch the spring the additional 3.9 cm. Watch your units. x here should be in meters.
anonymous
  • anonymous
the k is very high
anonymous
  • anonymous
k=26465 your ans is around 40. something

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
thanks eashmore that helped a lot and yes mythias that is what I got and it turned out to be correct
anonymous
  • anonymous
ok perfect :)

Looking for something else?

Not the answer you are looking for? Search for more explanations.