anonymous
  • anonymous
find the average value o f over the region D: f(x,y) = xsin(y), D is enclosed by the curves y =0, y=x^2, and x=1
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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TuringTest
  • TuringTest
I suppose that means you divide by the area of the region
anonymous
  • anonymous
yeah i was given a formula that the double integral of f(x,y)DA = (area of R)(average value of f on R)
TuringTest
  • TuringTest
so you already have the value of the double integral can you find the area D (or R, or however you want to call it)? that's calc I stuff

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More answers

anonymous
  • anonymous
hang on I'm trying to solve for the double integral
TuringTest
  • TuringTest
oh I thought it was the same as the other, but it's a bit different
anonymous
  • anonymous
yeah just sine
anonymous
  • anonymous
is the double integral 1/2(1-sin1)
TuringTest
  • TuringTest
I got just -1/2sin1
TuringTest
  • TuringTest
oh wait, you were right
anonymous
  • anonymous
okay good you scared me :)
anonymous
  • anonymous
okay so how do i solve for the area of R?
anonymous
  • anonymous
integral of x^2?
TuringTest
  • TuringTest
just like the good old days of calc 1
anonymous
  • anonymous
the bounds given don't form a region though
TuringTest
  • TuringTest
sure they do|dw:1332297950352:dw|\[R=\int_{0}^{1}x^2dx\]
anonymous
  • anonymous
ahhhhh
anonymous
  • anonymous
so area = 1/3?
TuringTest
  • TuringTest
yep
anonymous
  • anonymous
so average = 3/2(1 - sin1)
TuringTest
  • TuringTest
guess so never had to find an average value like this, but it makes sense
anonymous
  • anonymous
awesome thank you so much!

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