anonymous
  • anonymous
find the area of a triangle with sides of length 7 and 9 and included angle 72 degree.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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amistre64
  • amistre64
the height if going to have something to do with the sin of 72
amistre64
  • amistre64
side1*side2*sin 72 / 2
anonymous
  • anonymous
|dw:1332298374511:dw|

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amistre64
  • amistre64
is that really an included angle?
anonymous
  • anonymous
the right angle no just the 72
anonymous
  • anonymous
so 38.52
amistre64
  • amistre64
an "included angle" is one the is nestled inbwteen the side lengths mentions
amistre64
  • amistre64
|dw:1332298527074:dw| this is what you gave us in your information
anonymous
  • anonymous
yea ... i drew it wrong i thought it was a triangle since it said find the area of a triangle
amistre64
  • amistre64
:) then "height" can be regarded as 7sin(72) ; a base as 9 area tri = hb/2 = 9*7sin(72)/2
anonymous
  • anonymous
so height 6.66
anonymous
  • anonymous
wait know i am confused
anonymous
  • anonymous
now*
anonymous
  • anonymous
\[1/2 \times7\times9\times \sin 72 = 29.95828026 \approx 30\]
anonymous
  • anonymous
so that is how you do it?
anonymous
  • anonymous
yes .. half x 1st side x 2nd side x sine the angle included between them :)

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