anonymous
  • anonymous
please help me! http://answers.yahoo.com/question/index;_ylt=AgOQpn2oHp1rjlOOJ_X9Y2rsy6IX;_ylv=3?qid=20120320195205AA6t5wt find the volume of the solid that results when the region bounded by x=(√5)y2 and the y-axis from y=-1 to y=1 is revolved around the y-axis
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
\[x=\sqrt{5}y ^{2}\] correct
anonymous
  • anonymous
What is the volume? I don't understand my homework. Number 2, 4, 5, 10, 11, 12 form practice problem set 26 please, help me!! http://books.google.com.co/books?id=5-SisV1sLm0C&pg=PA218&lpg=PA218&dq=find+the+volume+of+the+solid+that+results+when+the+region+bounded+by+x%3D(√5)y2+and+the+y-axis+from+y%3D-1+to+y%3D1+is+revolved+around+the+y-axis&source=bl&ots=9nYt8kYaIk&sig=9ap_aYFgZw96zBO4LEZihUwABRM&hl=es-419&sa=X&ei=Qj9pT73TH6mlsALKkL2LCQ&ved=0CB0Q6AEwAA#v=onepage&q=find%20the%20volume%20of%20the%20solid%20that%20results%20when%20the%20region%20bounded%20by%20x%3D(√5)y2%20and%20the%20y-axis%20from%20y%3D-1%20to%20y%3D1%20is%20revolved%20around%20the%20y-axis&f=false
anonymous
  • anonymous
am i correct in my assumption for the equation that you typed on yahoo answers?

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anonymous
  • anonymous
yes :)
anonymous
  • anonymous
ok this is whats known as the washer method. it is called the washer method because as the object revolves around the y-axis in this case, a hole is made in the middle. our formula will be as follows
anonymous
  • anonymous
\[\pi \int\limits_{c}^{d}(f(y))^{2} dy\]
anonymous
  • anonymous
then you just integrate, plug in your interval and tha tis your answer
anonymous
  • anonymous
what is the radius of the hole? I suppose that the radius of the "disc" (using the disc method, not shell) would be the original equation ([x=\sqrt{5} y ^{2}\]), right?
anonymous
  • anonymous
but what about the hole? or the radius is 1? I am really confused :S
anonymous
  • anonymous
the radius of the hole made by the revolution is accounted for in the formula
anonymous
  • anonymous
understand?
anonymous
  • anonymous
ok. but then what would be the radius of the other part, is it 1, because it is from y=1 to y=-1. so then the formula would be πS(1 to -1) (R-r)^2 dy R=? and r=\[x=\sqrt{5}y ^{2}\]

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