anonymous
  • anonymous
how do i convert from rectangular to parametric
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
Solve for tin one of the equations, Substitute into the second equation ,Simplify
anonymous
  • anonymous
y= 4/5 t + 7/5
anonymous
  • anonymous
i mean not t y= 4/5 x + 7/5

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More answers

anonymous
  • anonymous
how do i solve that for t?
anonymous
  • anonymous
\[x = rcos \theta, y = rsin \theta\]
anonymous
  • anonymous
|dw:1332301409919:dw|
anonymous
  • anonymous
|dw:1332301566423:dw|
TuringTest
  • TuringTest
you converted to polar form math8g, not parametric
amistre64
  • amistre64
lol, but its a nice polar ;)
anonymous
  • anonymous
misread ...darn sorry
amistre64
  • amistre64
y(t)= 4/5 x(t) + 7/5
anonymous
  • anonymous
the answer the book got was x=5t-2 and y=6-4t
anonymous
  • anonymous
it asks me to find the parametric representation of a line that runs through (-2,6) and (3,2)
TuringTest
  • TuringTest
well that makes it a lot easier
TuringTest
  • TuringTest
first find a vector that point from one point to the next what is that vector?
anonymous
  • anonymous
i have no idea. i got the equation of a line in rectangular form though
anonymous
  • anonymous
would it be (5,-4)?
TuringTest
  • TuringTest
that get's us farther away from where we want to be yes the vector is \(\vec r=<5,-4>\) the formula for a vector equation of a line is....
TuringTest
  • TuringTest
I should have called that \(\vec v=<5,-4>\) the formula for the line is\[\vec r=\vec r_0+t\vec v\]where \(\vec r_0\) is one of the given points the line passes through
TuringTest
  • TuringTest
so we have\[\vec r=<-2,6>+t<5,-4>=<-2+5t,6-4t>\]
TuringTest
  • TuringTest
looking at each component individually we get your books answer
TuringTest
  • TuringTest
you should really read this to get a good handle on what we just did http://tutorial.math.lamar.edu/Classes/CalcII/EqnsOfLines.aspx
anonymous
  • anonymous
okay thank you
TuringTest
  • TuringTest
welcome :)
anonymous
  • anonymous
it is possible to get the same rectangular equation, even though the parameter is different and the parametric equations are different depending on the choice on x1 , y1
amistre64
  • amistre64
youll get the same direction vector; but you can use any point on the line to anchor it too; and any scalar of the vector itself
anonymous
  • anonymous
|dw:1332303236619:dw|
anonymous
  • anonymous
|dw:1332303554044:dw|

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