anonymous
  • anonymous
Find sin2x cos2x tan2x from the following: csc(x)=4, tan(x) < 0
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
is the answer cos2x = 3/4 sin2x = rad(7)/4 tan2x = rad(7)/3 ?
anonymous
  • anonymous
|dw:1332306851166:dw|
anonymous
  • anonymous
|dw:1332307017512:dw|

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anonymous
  • anonymous
can you do the rest?
Callisto
  • Callisto
note that the angle is in quadrant II as cscx is +ve while tanx is -ve
anonymous
  • anonymous
oops... I didn't read ... again ... getting tired gd nite !
anonymous
  • anonymous
|dw:1332307335450:dw|
anonymous
  • anonymous
so its sin2x = -rad(15)/4 cos2x = 3/4 tan2x = 8rad(15)
anonymous
  • anonymous
???????????
anonymous
  • anonymous
|dw:1332308949617:dw|
anonymous
  • anonymous
look for the double angles formulas and just substitute in the values above
Callisto
  • Callisto
|dw:1332309041482:dw|
Callisto
  • Callisto
\[\cos 2x = 2\cos^2x-1\]\[\tan2x = (2tanx)/(1-\tan^2x)\]

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