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Chena804

  • 2 years ago

The height in feet of an object dropped from an 18- foot stepladder is given by h(t)=-16t^2+18 , where t represents the time in seconds after the object is dropped. How long does it take the object to hit the ground? (Hint: The height is 0 when the object hits the ground. Round to the nearest hundredth of a second.) Please show steps.

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  1. luke23
    • 2 years ago
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    0=-16t^2+18 t^2=18/16 t=sqrt(18/16)

  2. Chena804
    • 2 years ago
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    The answer is 1.06 seconds. I am not sure how to get to the answer.

  3. luke23
    • 2 years ago
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    sqrt(18/16) = 1.06 , just set the equation to equal 0. after all you are trying to solve t when height is 0 as this is how much time has passed. just do what i did.

  4. Chena804
    • 2 years ago
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    Thank you for the help.

  5. luke23
    • 2 years ago
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    all g

  6. Chena804
    • 2 years ago
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    Yep.

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