Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

Chena804

  • 4 years ago

The height in feet of an object dropped from an 18- foot stepladder is given by h(t)=-16t^2+18 , where t represents the time in seconds after the object is dropped. How long does it take the object to hit the ground? (Hint: The height is 0 when the object hits the ground. Round to the nearest hundredth of a second.) Please show steps.

  • This Question is Closed
  1. luke23
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    0=-16t^2+18 t^2=18/16 t=sqrt(18/16)

  2. Chena804
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    The answer is 1.06 seconds. I am not sure how to get to the answer.

  3. luke23
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    sqrt(18/16) = 1.06 , just set the equation to equal 0. after all you are trying to solve t when height is 0 as this is how much time has passed. just do what i did.

  4. Chena804
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    Thank you for the help.

  5. luke23
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    all g

  6. Chena804
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    Yep.

  7. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy