anonymous
  • anonymous
Easy, try it out guys, Given 6 different toys of green colour, 5 different toys of blue colour and 4 different toys of red colour, the combination of toys that can be chosen taking atleast one green and one blue toys are ?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
@Ishaan94
Callisto
  • Callisto
how many are you choosing each time?
pokemon23
  • pokemon23
what type of question does this category follow to probability ?

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More answers

anonymous
  • anonymous
@Callisto: Any combination ;-)
anonymous
  • anonymous
@pokemon23: Combinatorics
pokemon23
  • pokemon23
Interesting when do you learn combinatorics?
Callisto
  • Callisto
should i list out all possibility ?
anonymous
  • anonymous
Is it (11)9! ? heh :$
Callisto
  • Callisto
i think ' the combination of .... are' is not the same as ' how many combinations ..'? :S
anonymous
  • anonymous
\( (2^6-1)\times (2^5-1)\times 2^4 \)
Mani_Jha
  • Mani_Jha
You can do it in two ways: 1)6C1x5C1(4C0+4C1+4C2+4C3+4C4)+6C2x5C1(4C0+4C1+4C2+4C3+4C4)+6C3x5C1(4C0+4C1+4C2+4C3+4C4)+.......+6C6x5C1(4C0+4C1+4C2+4C3+4C4).. =5C1(6C0+6C1+6C2+6C3+...6C6)(4C0+4C1+4.. 2)The total no of ways of choosing atleast one from 6 green balls is (2^6-1) The total no of ways of choosing atleast one from 5 blue balls is (2^5-1) The total no of ways of choosing any from 4 red balls is (2^4) Both will give the same answer! xD

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