anonymous
  • anonymous
{2/n^2} from n=5 to inf how do we know that this sequence is bounded below by zero?
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
because 0 cannot be in the denominator
anonymous
  • anonymous
then {(-1)^n+1} from n=1 to inf how do we know that it's bounded below by -1
anonymous
  • anonymous
I don't understand the definitions of both bounded below and above, what exactly it means?

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
"If there exists a number m such that for every n we say the sequence is bounded below. The number m is sometimes called a lower bound for the sequence." "If there exists a number M such that for every n we say the sequence is bounded above. The number M is sometimes called an upper bound for the sequence." from Paul's online Notes. here is the link if u r intersted: http://tutorial.math.lamar.edu/Classes/CalcII/MoreSequences.aspx
anonymous
  • anonymous
that's what I am reading at the moment :)
anonymous
  • anonymous
thanks anyway
anonymous
  • anonymous
also in simple terms, when they say m is the lower bound, it means no value in the sequence/series can go below the value of m :)

Looking for something else?

Not the answer you are looking for? Search for more explanations.