anonymous
  • anonymous
Sketch the graph of x=t^2 y=1/t for t>0
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
Is it like this?|dw:1332336280965:dw|?
anonymous
  • anonymous
t is? A constant or variable?
anonymous
  • anonymous
t >0 And value greater than 0

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anonymous
  • anonymous
any value greater than 0, sorry.
anonymous
  • anonymous
|dw:1332183657909:dw| It will be a parabola.
anonymous
  • anonymous
For the precise grap http://www.wolframalpha.com/input/?i=x+%3D+t%5E2
anonymous
  • anonymous
*graph
anonymous
  • anonymous
True, but won't values for the graph be: t 1 2 3 4 x 1 4 9 16 y 1 1/2 1/3 1/4.......?
anonymous
  • anonymous
You want a graph between x and y?
anonymous
  • anonymous
Yes
anonymous
  • anonymous
x= t^2 y= 1/t t>0
anonymous
  • anonymous
Then you would have to eliminate t. x = t^2 y = 1/t ---- Squaring this => y^2 = 1/t^2 or t^2 = 1/y^2 Therefore x = 1/y^2
anonymous
  • anonymous
|dw:1332183984675:dw| Something like that.
anonymous
  • anonymous
http://www.wolframalpha.com/input/?i=x+%3D+1%2Fy%5E2
anonymous
  • anonymous
^^ Exact graph.
anonymous
  • anonymous
Ok, but the second won't be like that, because the values have to be greater than 0
anonymous
  • anonymous
So, the left side would be cut out?
anonymous
  • anonymous
No. t > 0 Implies x > 0. Notice in grah x is the vertical axis. So there is no negative x. Hence, graph is asit isfor t > 0
anonymous
  • anonymous
|dw:1332184236583:dw| Normal axis - Simply shifted it 90 degree.
anonymous
  • anonymous
Oh, Ok., but if t>0, all values for x will be greater than 0
anonymous
  • anonymous
Yes.
anonymous
  • anonymous
So... same for y values... So won't it just be in one corner?
anonymous
  • anonymous
Its y^2. Remember that is always positive. So for a negative x You would need y to be imaginary. On our axis there will never be a negative x.
anonymous
  • anonymous
As x = 1/y^2 -- Always +ve
anonymous
  • anonymous
So, both values remain positive... so won't the curve/parabola just be in one corner of the grid?
anonymous
  • anonymous
Sorrry. Forgot the y = 1/t. My bad. You are right.
anonymous
  • anonymous
Yea :) Thanks for helping though :D
anonymous
  • anonymous
Anytime :D
anonymous
  • anonymous
Anytime :D

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