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elica85
 3 years ago
the potential as a function of position x is shown in the graph...
elica85
 3 years ago
the potential as a function of position x is shown in the graph...

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elica85
 3 years ago
Best ResponseYou've already chosen the best response.1i tried to draw a smooth curve

elica85
 3 years ago
Best ResponseYou've already chosen the best response.1is the electric field zero at x=0? is the max magnitude at 15 or 5cm?

ash2326
 3 years ago
Best ResponseYou've already chosen the best response.2Electric Field is defined as \[E=\frac{dv}{dx}\] v= potential so E is the negative of the slope of the potential curve. Do note that E found from this relation is the E in x  direction. At x=0 the curve is parallel to x axis, that is it's constant so E=0 At x=5 the slope is negative and magnitude wise the highest. So E will be max at x=5 cm

elica85
 3 years ago
Best ResponseYou've already chosen the best response.1how do you determine that the curve is parallel to x axis @ x=0? it doesn't look like it on my graph but in the actual graph, it looks parallel at x=10 too

elica85
 3 years ago
Best ResponseYou've already chosen the best response.1i assumed E was zero at x=0 since d(v=0) should be zero so E=(d0)/dx=0

ash2326
 3 years ago
Best ResponseYou've already chosen the best response.2No if v=0 doesn't mean that E=0 but the negative of slope of V is E, Yeah at x=10 also the slope is zero. So there also E is zero

elica85
 3 years ago
Best ResponseYou've already chosen the best response.1hmm still confused. i need the negative of the slope of V to find where E is zero? or to find the max magnitude? and which direction is the E at the max point?

elica85
 3 years ago
Best ResponseYou've already chosen the best response.1dw:1332352015313:dw is this what the graph of E look like?

ash2326
 3 years ago
Best ResponseYou've already chosen the best response.2Ok Elica, Yeah Electric field is the negative of the voltage's slope. When we have Voltage constant or parallel to axis. Then it's slope is zero and consequently E is zero

elica85
 3 years ago
Best ResponseYou've already chosen the best response.1ok i understand. so is the graph i did for E right?

ash2326
 3 years ago
Best ResponseYou've already chosen the best response.2If V is cos then E will be sine

ash2326
 3 years ago
Best ResponseYou've already chosen the best response.2x=0, v=constant so E will be zero

elica85
 3 years ago
Best ResponseYou've already chosen the best response.1ok so it's not right. how do i determine the direction of E at x=0 or x=10?

ash2326
 3 years ago
Best ResponseYou've already chosen the best response.2E is in the x direction always:)

ash2326
 3 years ago
Best ResponseYou've already chosen the best response.2Yeah, when E is negative that means it's in x direction

ash2326
 3 years ago
Best ResponseYou've already chosen the best response.2Welcome, Did you understand?

elica85
 3 years ago
Best ResponseYou've already chosen the best response.1yes, that was great help
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