• anonymous
[Polar Coordinates] Why dA = r dr d(theta)? I can't understand why is r dr. D. Auroux says it's because r d(theta) is the base of a rectangle, but doesn't this works only if we consider dA near the border? We do want to compute dA everywhere. What happens if dA is not on border, but somewhere else in the quadrant? Shouldn't we reduce the length of r?
MIT 18.02 Multivariable Calculus, Fall 2007
• Stacey Warren - Expert brainly.com
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