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Simplify the following expression: 8^2 /the square root of 16 + 5^2 - 8 forty-nine twenty-one thirty-three forty-three

Mathematics
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anything with a ^2 after it is supposed to be squared
Is that: \[\frac{8^2}{\sqrt{16+5^2-8}}\]
\[8\div \sqrt{16}+5^{2}-8\]

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Other answers:

\[\frac{8}{\sqrt{16}}+5^2-8 \]
so its \[1+5^{2}-8\]?
\[\sqrt{16}=4\]
or actually its \[2+5^{2}-8?\]
Yes
then you simplify the 5 squared to \[2+25-8\]
yes!
so 2+25 = 27 27-8 = 19?
yes!
then what because 19 is not an answer and im lost after that.......
\[\frac{8}{\sqrt{16}}+5^2-8=\frac{8}{4}+5^2-8=2+25-8=27-8=19\] Yep it is the answer! Be sure that the problem I have looks exactly like the problem you have.
o i see thank you alot!

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