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sorry, was on phone. This one?
yes and no problem
Ok, so slope intercept form is Y = m*x + b m is the slope b is the y intercept So for your problem, the slope = m = 1/2 and the y intercept is b = -5 then put into the equation Y = (1/2)*x + (-5) Y=(1/2)*x - 5
so does this have an = in it or do i leave it like that
Y = (1/2)*x - 5 Yes, this has a = sign
i see that i have to graph the line as well
ok. so plot the point (0,-5)
Then count up one square and to the right two squares and draw another point. connect the dots.
and draw a line extending beyond the dots too. you can keep counting up one, to the right two places
Y = (1/2)*x - 5 if y = 0, solve for x for another point: 0 = (1/2)*x-5 5=(1/2)*x x=10 so you can plot the point (10,0) also
so i can plot both or either or?
you can plot either way. by using (0,-5) and then counting up one over two for the slope, or you can plot (0,-5) and (10,0) and connect with line
okay i got it
you could use both methods too, just for verification, like for an exam or something, where it is important.
this is my school final exam lol
Note that the counting method for the slope is because 1/2 = y/x = the change in y over the change in x. if the slope was negative the line would be perpendicular to the line drawn, and then it would be down/right.
ah, right, my short term memory. :)
so if it is final, hopefully this stuff isn't too new to you :) just need a refresher
also you should probably complete the line extended to the right to intersect the x axis, but my picture ran out of room
plot (0,-5) and (10,0) and connect with line --> is probably most accurate and proper
okay are we ready for the next one if you have time i only got 3 after the one im about to post
i can help a little more