Jose is paying for a two dollar drink using bills in his wallet. He has four one dollar bills, two five dollar bills, and two ten dollar bills. If he selects two bills at random, one at a time from his wallet, without replacement, what is the probability that he will choose two one dollar bills to pay for the drink?
Show your work.
Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
Not the answer you are looking for? Search for more explanations.
NO you cant make me, im adorable remember? :D and i sent you a message, you never replied
The fact that the outcome of choosing the first bill affects the outcome of choosing the second bill makes these events dependend. ( without replacement)
E1 = Event that the first bill is a one dollar bill.
E2 = Event that the second bill is a one dollar bill.
P(E1) and E2) = P(E1) and P(E2|E1)
P(E1) and P(E2|E1) = P(E1)*P(E2|E1)
There are 4 + 2 + 2 = 8 bills to choose from.
a) P(E1) = 4/8
prob. of choosing 1 of the 4 one dollar bills from 8 bills
b) P(E2|E1) = 3/7
prob. of choosing 1 of the remaining 3 one dollar bills from remaining 7 bills
c) P(E1 and E2) = P(E1)*P(E2|E1) =(4/8) * (3/7) = 3/14
Answer is 3/14 = 0.214286