anonymous
  • anonymous
(x^2-2x-15)/(x+3) Isnt it has a vertical asymptote at x=1? but how come if i graph it, it only shows a straight line but not approching to x=1 http://www.wolframalpha.com/input/?i=%28x%5E2-2x-15%29%2F%28x%2B3%29
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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apoorvk
  • apoorvk
vertical asymptote at x=-3. i know i graphed it too on th enet, but it seems we have misunderstood the command to the application. we need to redefine it.
anonymous
  • anonymous
srry i actually mean horizontal asymptote
anonymous
  • anonymous
actaully its best to factor the numerator first, and see what divided out. In this case the x+3 in the denminator will be gone

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anonymous
  • anonymous
even from the graph you see that this will be a line
anonymous
  • anonymous
so there will be no horizontal asymptote in this case? I dont know when the H.A is 0 and when is none..
anonymous
  • anonymous
correct there is no horizaontal asymptote. There wil be no horixaontal asympotote when the degree of the numerator is higer than the denomonator
anonymous
  • anonymous
so if it is 5/x , there is still a H.A of 0?
anonymous
  • anonymous
yes and a veritcal asymptote at x=0
anonymous
  • anonymous
oh ok thank so much!! its clear now :)

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