I need help with finding the element that is oxidized and reduced.
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Argh!@! I've typed my answer twice and both times OS refreshed itself on me...
oxidization is loss (of electrons)
Reduction is Gain (of electrons)
In the reactants, Rb isn't reacting with anything so its charge is 0. The iodines are covalently sharing electrons, so their charges are 0 as well.
To form the ionic soilid RbI, rubidium gives up 1 electron to iodine since Rb is an alkali metal while I is a halogen. Since Rb loses an electron its charge in RbI is +1, I's charge is -1 since it gains an electron.
When an atom loses electrons, it is oxidized. When an atom gains electrons, it is reduced.
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I iodine is a halogen so its atoms have 7 electrons in the outer shell
Rb Rubidium is a alkali metal so it has 1 electron in the outer shell
The molecule is formed as the 1 electron from the metal goes to the halogen
ie Rb has lost its electron, - it has been oxidized
I has gained the electron - it has been reduced