anonymous
  • anonymous
2Rb+I2---> 2RbI I need help with finding the element that is oxidized and reduced.
Chemistry
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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Rogue
  • Rogue
Argh!@! I've typed my answer twice and both times OS refreshed itself on me...
UnkleRhaukus
  • UnkleRhaukus
O.I.L R.I.G oxidization is loss (of electrons) Reduction is Gain (of electrons)
Rogue
  • Rogue
In the reactants, Rb isn't reacting with anything so its charge is 0. The iodines are covalently sharing electrons, so their charges are 0 as well. To form the ionic soilid RbI, rubidium gives up 1 electron to iodine since Rb is an alkali metal while I is a halogen. Since Rb loses an electron its charge in RbI is +1, I's charge is -1 since it gains an electron. When an atom loses electrons, it is oxidized. When an atom gains electrons, it is reduced.

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UnkleRhaukus
  • UnkleRhaukus
I iodine is a halogen so its atoms have 7 electrons in the outer shell Rb Rubidium is a alkali metal so it has 1 electron in the outer shell The molecule is formed as the 1 electron from the metal goes to the halogen ie Rb has lost its electron, - it has been oxidized I has gained the electron - it has been reduced

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