anonymous
  • anonymous
solve for X using x^2+bx=-c x^2-x+5 so x^2+8x=-5 but than im stuck
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
where did you get the 8 from?
anonymous
  • anonymous
woops accidently took that from a different problem im working on
anonymous
  • anonymous
problem is x^2-x+5=0

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anonymous
  • anonymous
i think i use the equation x^2+b/a x = -c/a
anonymous
  • anonymous
use the quadratic formula to solve
anonymous
  • anonymous
or do you have to do it the way you have it up there ^^^?
anonymous
  • anonymous
up there
anonymous
  • anonymous
and that is where im getting lost. Let me try quadratic really fast
anonymous
  • anonymous
quadratic works. I think i got it now lol
anonymous
  • anonymous
oh wait no it doesnt because i get 1-20 within the rational...
anonymous
  • anonymous
x^2-x+5=0 x^2-x=-5 x^2=-5+x x=sqrt(-5+x)
anonymous
  • anonymous
so this problem has no solution than
anonymous
  • anonymous
because i get 1±√1-20/2
anonymous
  • anonymous
and the square cant be negative right
anonymous
  • anonymous
that's the solution. it's just not exact. and squares shouldn't be negative.
anonymous
  • anonymous
Hmm... ok thanks

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