anonymous
  • anonymous
Simplify each radical expression. Assume that all variables are positive 1) \[\sqrt{49x^2y^{10}}\] 2) \[\sqrt[3]{-64y^9}\] 3) \[\sqrt[3]{54xy^5}\] Please explain and show work!
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
can someone help @amistre64 @AnimalAin @Mertsj @Luis Rivera @eseidl @KingGeorge
KingGeorge
  • KingGeorge
Factor each equation out into a square/cube root of three different things. Your actual number, an x-term, and a y-term. Do you have a guess as to what the answer to the first one is?
anonymous
  • anonymous
|dw:1332369703773:dw|

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More answers

KingGeorge
  • KingGeorge
Correct.
anonymous
  • anonymous
I don't know how to do the cube root ones :(
anonymous
  • anonymous
@KingGeorge ?
anonymous
  • anonymous
@hero ?
Mertsj
  • Mertsj
Can't read them.
Mertsj
  • Mertsj
\[\sqrt[3]-64{y^9}=-4y^3\]
anonymous
  • anonymous
@Mertsj |dw:1332373305202:dw|
Hero
  • Hero
the answer to the first one is correct 7xy^5
anonymous
  • anonymous
@hero what about the rest idk how to do it :(
Hero
  • Hero
Use the same method you used for the first one
Hero
  • Hero
|dw:1332374107905:dw|
anonymous
  • anonymous
-4?
Hero
  • Hero
how do you end up with -4?
Hero
  • Hero
Sorry @mertsj, I didn't mean to wak you.
Hero
  • Hero
wake you*
Mertsj
  • Mertsj
|dw:1332374425171:dw|
Mertsj
  • Mertsj
Yeah...you stop that. We old people need our sleep!!! lol
Mertsj
  • Mertsj
\[\sqrt{49x^2y ^{10}}=\sqrt{7^2x^2(y^2)(y^2)(y^2)(y^2)(y^2)}=7xyyyyy=7xy^5\]
anonymous
  • anonymous
@hero the -4 from the cube root of -64
Hero
  • Hero
@trolololcat, I was giving you a hint for the last one
anonymous
  • anonymous
how did you get from the power of 9 to the power of 3 on the second one?
anonymous
  • anonymous
|dw:1332375221688:dw|
anonymous
  • anonymous
sorry that was really bad drawn lmao
anonymous
  • anonymous
|dw:1332375545087:dw|
.Sam.
  • .Sam.
y cubed, or cube root?
anonymous
  • anonymous
cube root
Mertsj
  • Mertsj
|dw:1332376442798:dw|
anonymous
  • anonymous
i don't understand where you got the ^12 from
anonymous
  • anonymous
@Mertsj
Mertsj
  • Mertsj
I just made it up as an example so you could see how the 3rd root works.
anonymous
  • anonymous
@mertsj, for the thone, can you explain why my answer i drew was wrong?
Mertsj
  • Mertsj
Because you rewrote 54 as 3 times 18 and then you said that the third root of 3 is 3 and of course that is false.
Mertsj
  • Mertsj
|dw:1332380861459:dw|

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