anonymous
  • anonymous
can someone help me out with these graph problems I only need help with 3 problems please the first problem is Y=2x-8 this problem is suppose to have lines with incline
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
This is the equation of a straight line. You need two points and then just draw a line through them. If we set x=0 we get y=-8 so one point is (0,-8). To get another point set y=0. This gives x=4. So another point is (4,0). Plot these points and draw a line through them. Your incline (or "slope) is m=2.
anonymous
  • anonymous
can you show me what you mean Please I am really bad at this stuff
anonymous
  • anonymous
|dw:1332370751548:dw|

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anonymous
  • anonymous
5x – 5 = 3x – y this is suppose to have a is suppose to have lines with incline to can you help me with this last problem please
anonymous
  • anonymous
ok, so first you have to group the like terms (do the subtraction on the right hand side). \[5x-5=2y\]Now divide both sides by two:\[y=\frac{5}{2}x-\frac{5}{2}\]
anonymous
  • anonymous
now, set x=0 to get the first point on the line: \[y=\frac{5}{2}(0)-\frac{5}{2}=\frac{5}{2}\]so one point is (0,-5/2)
anonymous
  • anonymous
Now any other value of x can be used to get another point on the line. for example x=2:\[y=\frac{5}{2}(2)-\frac{5}{2}=5-\frac{5}{2}=\frac{5}{2}\]so another point is (2,5/2)
anonymous
  • anonymous
can you show me what this would look like please?
anonymous
  • anonymous
|dw:1332371438773:dw|something like this
anonymous
  • anonymous
slope is m=5/2=2.5
anonymous
  • anonymous
thank you for helping me It is so hard to find people to help me out
anonymous
  • anonymous
np :) hope it helped

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