MULTIPLE CHOICE MULTIPLE CHOICE!! In a population of plants, the allele for long stems (S) is completely dominant over the allele for short stems (s). If 35% of the population has short stems, calculate the percentage of the population that is expected to be heterozygous (Ss).
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Really, its always the best answer for when you need help on these things.
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how many parents does it take to create 1 offspring?
Really, I thought a Punnet Square would have helped with everything. Don't take my answer!
punnet was my idea too :)
but that assumes 2 parents are needed
is it autosomal or xy somal?
im begining to think there isnt enough information presented
that is not any of the choices........
well, it would help if you had some sort of input to guide us along with; taking blind stabs at it is the best we can do.
choose a multiple choice that is given.....
64 total in the second generation; assuming the start was good; and only 4 so far have ss
400/64 = 6.25% with ss ....
theres prolly an easier way to determine this ....
Point 1. There is enough info to answer the question. Point 2. You really should not set up dihybrid crosses when you only have two alleles of the same gene on two different chromosomes.
To solve it, you use the Castle - Hardy - Weinburg theorem which states that the p^2 + 2pq + p^2 = 1 where p is the probability of a homozygous dominant genotype (SS), q is the probability of a homozygous recessive phenotype (ss) and 2pq is the probability of a heterozygous phenotype.
So you set up your equation:
p^2 + 2pq + 0.35 = 1.
q = sqrt(0.35) = 0.5916.
Sub that into the equation for q:
p^2 + 1.1832p + 0.35 = 1.
Solve it for p and you get ~0.408 which rounds to the third option, 40%.
There are some caveats and assumptions made about genentic frequencies being in equilibrium in the population and there not being any genetic drift (so in that sense there isn't enough info to solve the problem) but in general, that's the solution.