anonymous
  • anonymous
PLEASE HELP-I have 2 questions! 1-Know the Trigonometric ratios and how they are used. 2-Be sure to know their reciprocal functions
Mathematics
  • Stacey Warren - Expert brainly.com
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jamiebookeater
  • jamiebookeater
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UnkleRhaukus
  • UnkleRhaukus
those arn't questions
anonymous
  • anonymous
well, i kinda wrote it in my own form. but i need to know what trigonometric ratios are and how they are used. And, i need to know the reciprocal functions
anonymous
  • anonymous
i dont understand what reciprocal functions are and the 2st problem as well.

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anonymous
  • anonymous
1st*
UnkleRhaukus
  • UnkleRhaukus
well have you herd if the sine function \[\sin(\theta)=\frac{opp}{hypo}\] the sine of an angle is a measure of the ratio of 'the opposite side' to 'the hypotenuse' of a right angled triangle |dw:1332376356208:dw|
UnkleRhaukus
  • UnkleRhaukus
the sine of theta will never be greater than 1 because if the opposite side was greater than the hypotenuse , you wouldn't have a right angled triangle when the angle theta is small the ratio is small
UnkleRhaukus
  • UnkleRhaukus
we can use this relationship between the angle and the ration of side lengths to calculate stuff for example|dw:1332376626442:dw| you wish to determine the height of the tree (Which is growing at a right angle to the ground) , you know that at some distance away there is an angle between the top of the tree and where you are standing
UnkleRhaukus
  • UnkleRhaukus
we can use trigonometree the height of the tree is the opposite side of the triangle the distance between you and the tree is the adjacent side theta is the angle
UnkleRhaukus
  • UnkleRhaukus
in this case a different trig ratio will be used the tangent \[\tan{\theta}=\frac {opp}{adj}\] |dw:1332377130511:dw|
anonymous
  • anonymous
o_o wow lol, thank you :]
UnkleRhaukus
  • UnkleRhaukus
say we have a tape measure and measure the adjacent side to be 40 meters and a sextant (angle measurer) and measure the angle to be 30 degrees
UnkleRhaukus
  • UnkleRhaukus
if we now take the tangent of 30 degrees \[\tan(30)=\frac{opp}{adj}=\frac{height}{40m}\] a calculator,(,.. table or some other method) may be used to to find \[\tan30 = 0.577= \frac{1}{\sqrt{3}}\]
UnkleRhaukus
  • UnkleRhaukus
putting this together \[\frac{1}{\sqrt{3}}=\frac{height }{40m}\] which can be rearranged to solve for the height \[height=\frac{40}{\sqrt3}\approx 23.1m\]
UnkleRhaukus
  • UnkleRhaukus
which even looks about right for the diagram
UnkleRhaukus
  • UnkleRhaukus
|dw:1332378246089:dw|

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