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Find the lengths of the missing sides in the triangle. Write your answers as integers or as decimals rounded to the nearest tenth. Diagram is not drawn to scale. https://www.connexus.com/content/media/456845-2232011-94631-AM-694817531.png

Mathematics
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wasn't this just solved?
no he didn't answer
he just said 7 i don't understand

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Other answers:

ok, so more info requested ?
yes
i want to know how to do it
ok. This type of triangle with the 90degrees and the 45degrees is a special type of triangle. Isosceles, i think. This means that the 7 side and the y side are always equal. the 45degrees and the unlabeled angle are the same, because the angles of the triangle add to 180. so, 180 - 90 -45 = 45. the unknown angle is 45degrees. Which also proves that the sides, 7 and y are the same length. Then to find x, you can use Pathagorean's theorem. (spelling?) ... which says \[C^2 = A^2 + B^2\] where C is the hypotenuse (across from the right angle), and A and B are the other sides. So, for your problem, \[x^2 = 7^2 +7^2 = 49+49=98\] \[x = \sqrt{98}\]
Does that help?
Yesss c: it helps a ton! thanks so much. You sir, deserve a cupcake. <3 thanks!
female, but thanks!! yummy :)
Sorry, mam c:
no worries :)
good luck !!
Thanks love c:
at least e-cupcakes are calorie free :)
oh &, i hope you know, I'm not a troll. My name is just ridiculous so I can see how you would think that o.O.
my name was picked quickly since I had an important question that needed a quick answer :) based off an old email address so it didnt have my real name in it :) e-cupcakes is supposed to be funny, i hope. sadly, real ones just don't fit my diet currently
Hahaha, same for me! I had a question about math and I just finished talking to a friend about this guy who says "diabeetus" so i made that my name. haha. xD. & haha aww, that sucks :c
Ah well... all's good. Just spent a little bit too much time exercising the brain and not the body. I'm working on it though. Have a good night! good luck with your trig
you too c:
Thanks for the answer too. It helped me.. diabeetus, you go to CA??

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