use implicit differentiation to find the equation of the tangent line in the form y=mx+b at the point (-2,3)
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i worked out the whole thing and i came up with y=2/3x+13 but i really don't think i knew how to find my b, but I'm not sure that was my only problem
Alright to solve this take the derivative
2x + y*y' = 0
y' = y/2x
now to find the equation of the tangent line we use the formula
we have the point (-2,3)
so we know f(-2) = 3
and the x value we are looking at is -2
so a = -2
so we have
f'(x)(x+2) + 3
now we need to find f'(-2) and we have our equation of the tangent line to do this
sub in the point into the equation and solve for y'
y' = y/2x
y' = 3/2(-2)
y' = -3/4
we now have f'(-2) = -3/4
so the equation is
-3/4(x+2) + 3 = y