anonymous
  • anonymous
What is teh fourth degree Taylor polynomial for 1/ 1-x centered at x=-1 ?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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saifoo.khan
  • saifoo.khan
@satellite73
anonymous
  • anonymous
i guess satellite isnt coming...do u have an idea how 2 do this question saifoo
saifoo.khan
  • saifoo.khan
Sorry, i can't help but wait.

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saifoo.khan
  • saifoo.khan
@across . im sure she can help
bahrom7893
  • bahrom7893
Sabrina it's a simple formula from calc.. Let me get my Calc 2 review book
saifoo.khan
  • saifoo.khan
Happy birthday @across
bahrom7893
  • bahrom7893
Taylor series centered around c: |dw:1332386886518:dw| etc..
bahrom7893
  • bahrom7893
fourth degree means u go on until u get to (f''''(c)/4!)(x-c)^4
anonymous
  • anonymous
omg thats alot of substitution
anonymous
  • anonymous
is c the x=-1 value
bahrom7893
  • bahrom7893
yes but it is really simple. Sorry ill prolly make an arithmetic mistake right now.. just differentiate 4 times.. and plug in (x+1) a lot
bahrom7893
  • bahrom7893
yes c is -1
anonymous
  • anonymous
its ok ill do all the algebra i just needed help with the calc part...but one thing can u differentiate f
bahrom7893
  • bahrom7893
1/(1-x)=(1-x)^(-1) f(x)=(1-x)^(-1) f'(x)=(1-x)^(-2) (the signs will cancel out) f''(x)=2(1-x)^(-3) f'''(x)=6(1-x)^(-4) f''''(x)=24(1-x)^(-5)
anonymous
  • anonymous
you are aswesome =)
anonymous
  • anonymous
thnks for ur help
bahrom7893
  • bahrom7893
np

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