anonymous
  • anonymous
dy/dx of y = (sqrt cos(x))^x
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
|dw:1332389210380:dw|
anonymous
  • anonymous
|dw:1332389423333:dw|
anonymous
  • anonymous
you can also substitute y

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More answers

anonymous
  • anonymous
is that the same thing as >>> cos(x)lncos(x)-xsin(x)/(2cos(x))y' cuz that's what my textbook says
anonymous
  • anonymous
it should be ...
anonymous
  • anonymous
I could work it out more
anonymous
  • anonymous
in your second step, you brought down the 1/2 exponent, i don't think you can do that?
anonymous
  • anonymous
taking the ln of both sides already brought down the x exponent from the previous step
anonymous
  • anonymous
|dw:1332389906131:dw|
anonymous
  • anonymous
yeah but you already did that for "x"
anonymous
  • anonymous
|dw:1332389944217:dw|
anonymous
  • anonymous
I did it one step at the time ...
anonymous
  • anonymous
ohh
anonymous
  • anonymous
why would you do that! haha
anonymous
  • anonymous
tired ...I guess
anonymous
  • anonymous
I can get the book answer ... do you want me to do that ?
anonymous
  • anonymous
yes please
anonymous
  • anonymous
|dw:1332390085315:dw|
anonymous
  • anonymous
it's just getting the common denominator right? <_<
anonymous
  • anonymous
yes
anonymous
  • anonymous
I think you must typed the answer wrong ... could you check ?
anonymous
  • anonymous
i.e must've
anonymous
  • anonymous
did i? i got it. it's[ (cosxlncosx - xsinx) / 2cosx ]*y
anonymous
  • anonymous
yes ... same thing then
anonymous
  • anonymous
|dw:1332390725943:dw|
anonymous
  • anonymous
yeah roflmao
anonymous
  • anonymous
thanks, you still got some in you?
anonymous
  • anonymous
one more ... wake up at 4 45 :(
anonymous
  • anonymous
dangg. what for?
anonymous
  • anonymous
work
anonymous
  • anonymous
i see, i think i got this in the bag actually
anonymous
  • anonymous
i'll see you around mathg8
anonymous
  • anonymous
good luck !
anonymous
  • anonymous
thanks for your help
anonymous
  • anonymous
np

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