A community for students.
Here's the question you clicked on:
 0 viewing
 3 years ago
A car and a motorcycle whose average rates are in the ratio of 4:5 travel a distance of 160 miles. If the motorcycle travels 1/2 hour less than the car, find the average rate of each.
 3 years ago
A car and a motorcycle whose average rates are in the ratio of 4:5 travel a distance of 160 miles. If the motorcycle travels 1/2 hour less than the car, find the average rate of each.

This Question is Open

benice
 3 years ago
Best ResponseYou've already chosen the best response.14:5 means the is 4/5 the speed of the motorcycle d=s*t 160=s1*(t) 160=s2*(t30) s1*(t)=s2*(t30) 4/5s2*t=s2*(t30) 4/5s2*ts2*t=30*s2 cancel out s2 4/5*tt=30 1/5t=30 t=150 d=s1*t 160=s1*(5/2h) s1=64 d=s2*t 160=s2(2h) s2=80 64:80 8:10 4:5

phi
 3 years ago
Best ResponseYou've already chosen the best response.0In this problem you have 3 equations and 3 unknowns. The 3 unknowns are Sc, Sm, and t (speed of the car, speed of the motorcycle, and the time traveled t in hours) the ratio they give tells you \[ \frac{Sc}{Sm}= \frac{4}{5} \]
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.