anonymous
  • anonymous
Graph the relation in the table. Then use the vertical-line test. Is the relation a function? x:-1 , 1 , 2 , 1 y:3 , 0 , -1 , 2 , 3
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
Given 4 x-coordinates, and 5 y-coordinates? Hmm...
anonymous
  • anonymous
Seems okay to me.
anonymous
  • anonymous
We don't know what part of \(\{x\}\)'s domain is mapped to which part of \(\{y\}\)'s.

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anonymous
  • anonymous
What's wrong in treating as Injection?
anonymous
  • anonymous
this*
anonymous
  • anonymous
Ahh , these graphs annoy me ! lol
anonymous
  • anonymous
I am assuming: (-1,3),(1,0) ...
anonymous
  • anonymous
So this is a one-one function or injection.
anonymous
  • anonymous
Not sure how to treat this as an injection unless we're given more elements in \(y\) than in \(x\).
anonymous
  • anonymous
Woops, I mean equal.
anonymous
  • anonymous
Oh wait, not a bijection, ignore me. lol
anonymous
  • anonymous
Injection doesn't requires to be equal elements.
anonymous
  • anonymous
Sp do i just graph them ? or ..
anonymous
  • anonymous
and yes bijection and surjection does . lol it's okay :)
anonymous
  • anonymous
So*
anonymous
  • anonymous
Presumably you graph the first four points if each number of the domain's element corresponds to the codomain's? But then that requires we assume that's the case.
anonymous
  • anonymous
Actually i'll skip this one .

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