anonymous
  • anonymous
how do I find the equation with the following zeros: -1, 4-5i
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
multiply out (expand) the left side if you want standard form.
anonymous
  • anonymous
Where did the 3 come from? this is the answer I came up with x^3-7x^2+33x+41 for the first part that you show I came up with (x+1)(x-4+5i)(x-4-5i). Is this correct?
anonymous
  • anonymous
I have no idea!!! it's supposed to be the -1.

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More answers

anonymous
  • anonymous
since you list a complex root, it's conjugate is also a root so you actually have 3 roots: x = -1, x = 4-5i, x = 4+5i (conjugate)
anonymous
  • anonymous
lol I was freaking out over here!
anonymous
  • anonymous
so now just create your equation with the listed as your solution: (x--1)*(x-(4-5i))(x+(4+5i)) = 0
anonymous
  • anonymous
sorry, bout that!
anonymous
  • anonymous
no problem, I don't fully grasp all of the steps, but I think I'm doing most of it correctly, I just don't know where I am going wrong.
anonymous
  • anonymous
if you know the zeros to a function, always write it out in factored form then expand it.
anonymous
  • anonymous
lost internet connection for a while....
anonymous
  • anonymous
so you should get: x^3 - 7x^2 + 33x + 41 = 0
anonymous
  • anonymous
my screen froze
anonymous
  • anonymous
ok, I stumbled through it but that's what I came up with, it's just confusing.
anonymous
  • anonymous
do I need to put the =0 part?

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