antionette 3 years ago Find the distance between (1, 1) and (3, 4).

1. jaersyn

sqrt (x2 - x1)^2 + (y2 - y1)^2

2. hoblos

d^2 = (3-1)^2 + (4-1)^2 = 4+9=13 d=sqrt13

3. apoorvk

this is done using the distance formula... for any two points (x,y) and (x',y') the distance between them is.. $\sqrt{(x-x')^{2} + (y-y')^{2}}$ so here $^{13}$ should be it.

4. apoorvk

i mean root of 13, ie $\sqrt{13}$