anonymous
  • anonymous
Solve the following Triangle - SSS?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
Need to find all three angles: |dw:1332442987854:dw|
anonymous
  • anonymous
I tried law of cosines, but my calc said error domain...|dw:1332443040771:dw|
anonymous
  • anonymous
Any ideas?

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saifoo.khan
  • saifoo.khan
what we have to find?
anonymous
  • anonymous
We need to find the angle measures - A, B, and C
saifoo.khan
  • saifoo.khan
Let's find the angel A first. \[a^2 = b^2 + c^2 - 2bc (\cos A)\]Insert the values. \[22^2 = 17^2 + 31^2 -2(31)(17) \cos A\] \[-766 = -1054 \cos A\] \[\cos A = 383/527\] \[A = \cos^{-1} (\frac{383}{527})\]
saifoo.khan
  • saifoo.khan
Therefore A = 43.38*
anonymous
  • anonymous
@saifoo.khan I was taught to find the largest angle first, because if you were to use law of sin to find the largest angle, it would be incorrect, due to the ambiguous case. Where did I go wrong when I attempted to use law of cos to find the largest angle?
saifoo.khan
  • saifoo.khan
|dw:1332444581625:dw| i think it's +ve. ;)
anonymous
  • anonymous
That's a multiply sign. When you subtract the product of that away from 31^2, you get a negative
saifoo.khan
  • saifoo.khan
http://www.teacherschoice.com.au/maths_library/trigonometry/solve_4.gif
saifoo.khan
  • saifoo.khan
Sorry. but i never solve the question with respect to largest angle.
anonymous
  • anonymous
Okay, so how would I find the largest angle then? Because I need to find all 3 angles
saifoo.khan
  • saifoo.khan
Yes. find the second one as well. then use x + y + z = 180
anonymous
  • anonymous
So use law of cos two times then, use the sum of the angles in a triangle is equal to 180?
saifoo.khan
  • saifoo.khan
why times two? :O is it an isosceles triangle?
anonymous
  • anonymous
I meant find two angles of the triangle using law of cos, and then use the sum of the interior angles of a triangle is 180 to determine the third and the largest angle.
saifoo.khan
  • saifoo.khan
Perfect.

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