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freckles
 2 years ago
Best ResponseYou've already chosen the best response.1Now combine fractions! :)

freckles
 2 years ago
Best ResponseYou've already chosen the best response.1\[f'=\frac{2x(x^2)16}{x^2}\] right? :)

freckles
 2 years ago
Best ResponseYou've already chosen the best response.1Now set Mr.top=0! :) and solve for x We would look at where the bottom is 0 except our function is not even define for x=0 So we are only look for when the top of f' is 0

freckles
 2 years ago
Best ResponseYou've already chosen the best response.1Can you solve this for x?

freckles
 2 years ago
Best ResponseYou've already chosen the best response.1\[2x^316=0\] Yes that is the only real critical number \[x^38=0 \] \[(x2)(x^2+2x+4)=0\] x=2  \[b^24ac=2^24(1)(4)=416=12 <0 => x=2 \text{ is the only critical number}\] :) So good job! :)

freckles
 2 years ago
Best ResponseYou've already chosen the best response.1You deserve a medal! Seriously great job! :)
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