anonymous
  • anonymous
How do you find the two missing side lengths of a right triangle if you only know one side length and one angle measure (other than 90 degree angle)?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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Mertsj
  • Mertsj
Is it one of the special right triangles?
anonymous
  • anonymous
how do you know if its special ?
mysesshou
  • mysesshou
SOH CAH TOA works well. do you know it? sine, cosine, tangent.

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mysesshou
  • mysesshou
if it is a special triangle like angles 30, 60, 90 or 45, 45, 90, then there are rules for that too
anonymous
  • anonymous
yes i do(: and ohk thanks !
mysesshou
  • mysesshou
sides of 5, 12, 13 and 3, 4, 5 are also special triangles, but that doesn't really fit your question, since you only have one side. :)
anonymous
  • anonymous
yeah.. so do i just use SOH CAH TOA for it ?
mysesshou
  • mysesshou
those work. take the angle and the side you know and the side you want to know, and then choose which SOH CAH TOA you should use.
anonymous
  • anonymous
wait so does it matter which SOH CAH TOA i use ? or can it be any ?
mysesshou
  • mysesshou
SOH means sine for the sides that are opposite and hypotenuse. CAH means cosine, for the sides that are adjacent and hypot. TOA means use tangent, for the sides that are opposite and adjacent. |dw:1332468614322:dw|
mysesshou
  • mysesshou
|dw:1332468704659:dw|
anonymous
  • anonymous
ohk thanks ! i get it now ! thanks so much !!:D
anonymous
  • anonymous
could yu also use csc, cos, and sec ?
mysesshou
  • mysesshou
csc sec and such are just one over sine or one over cosine, etc. they don't really fit here. ......... i think. (been a real long time since I took the class. )
mysesshou
  • mysesshou
you can post that as a new question for a better answer. :)
anonymous
  • anonymous
ohk thanks !(:
mysesshou
  • mysesshou
\[\tan^{-1} (x/y) = \theta\] is how i think you solve or theta when working my prev pic
mysesshou
  • mysesshou
which might be different than those csc sec ones. i can't quite remember those as well.. .... sorry ! :)
anonymous
  • anonymous
haha its ohk ! thanks for trying tho ! :D

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