anonymous
  • anonymous
Find the derivatives of f(g(x)) and g(f(x)) f(u)=u^3, g(x)= 1/1+x
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
f= 3u^2 g= -1/(1-X)^2 i would think
Mertsj
  • Mertsj
Satellite appears and the crowd gathers.
anonymous
  • anonymous
just spacing out

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anonymous
  • anonymous
So you just find the derivatives and you don't have to use the chain rule?
anonymous
  • anonymous
nvm idk dont you mean x instead of u for the f(u)= U^3
anonymous
  • anonymous
\[f(g(x))=f(\frac{1}{1+x})=(\frac{1}{1+x})^3\] \[f(g(x))'=3(\frac{1}{1+x})^2\times \frac{-1}{(1+x)^2}\]
anonymous
  • anonymous
yes by the chain rule
anonymous
  • anonymous
yeah satellite is correct i was simply using wut u game me w/o subbing in for the f(g(x)) part
anonymous
  • anonymous
\[g(f(x))=g(x^3)=\frac{1}{1+x^3}\] \[g(f(x))'=-\frac{1}{(1+x^3)^2}\times 3x\]
raspberryjam
  • raspberryjam
Essentially you are finding the derivative of \[f(g(x))=(\frac{1}{1+x})^3\] and \[g(f(x))=(\frac{1}{1+x^3})\]
anonymous
  • anonymous
both clean up a tiny bit with some algebra
anonymous
  • anonymous
Ah makes sense. I see where I went wrong. Thanks everyone.
anonymous
  • anonymous
hey satellite are u good with calc 2? i got a few questions

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