anonymous
  • anonymous
y=sin(x^2)cos(x^2) find the derivative I think I'm supposed to do the product rule and I get sin(x^2)-sin(x^2)+cos(x^2)cos(x^)2 But what do I do after that?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
missing the chair rule
anonymous
  • anonymous
*chain rule
anonymous
  • anonymous
easiest to keep from getting bogged down in trig is to recall that \[\sin(x)\cos(x)=\frac{1}{2}\sin(2x)\]

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anonymous
  • anonymous
so you have \[\frac{1}{2}\sin(2x^2)\] take the derivative using the chain rule get \[\frac{1}{2}\cos(2x^2)\times 4x\] \[2x\cos(2x^2)\]
anonymous
  • anonymous
otherwise using chain and product rule it is a big fat mess
anonymous
  • anonymous
That makes it so much easier. Ya the chain rule was getting pretty busy. Thanks.

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