anonymous
  • anonymous
How do you find Arctan -sqrt3 without a calculator?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
Not sure what any of that means? This is 11th grade Trig; we've never covered any of that before?
anonymous
  • anonymous
LOL shes referring to calculus stuff
myininaya
  • myininaya
\[y=\arctan(-\sqrt{3}) \] \[\tan(y)=-\sqrt{3}=\frac{-\frac{\sqrt{3}}{2}}{\frac{1}{2}}\] |dw:1332471600065:dw|

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myininaya
  • myininaya
look in [-pi/2,pi/2] for solution
anonymous
  • anonymous
Still somewhat confused; is 330 going to be my answer?
amistre64
  • amistre64
if i recall correctly, you have to sacrifice about a dozen chickens to get an answer :)
myininaya
  • myininaya
no emclair look in the interval i mentioned
anonymous
  • anonymous
|dw:1332471855196:dw| i think the answer is 3/pi cuz arc tan is i over tan and tan of -root 3 is equal to pi over three but im not 100% positive
anonymous
  • anonymous
Okay; thanks, everyone!
myininaya
  • myininaya
-pi/3 is right

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