How many grams of zinc metal will react completely with 5.4 liters of 2.8 M HCl? Show all of the work needed to solve this problem.
Zn (s) + 2 HCl (aq) -> ZnCl2 (aq) + H2 (g)
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mol = molarity x volume
n = MV
5.4 L * 2.8 M HCl = 15.12 mol HCl
According to the balanced reaction, for every 2 moles of HCl, you need 1 mole of Zn to react. So for 15.12 mol HCl, you need 15.12/2 = 7.56 mol Zn. Now the molar mass of 65.4 g/mol. So in 7.56 mol Zn, there are 7.56 mol * 65.4 g/mol = 494. g Zn.
So you need 494 grams of zinc to react completely with 5.4 liters of 2.8 M HCl.
No.. This is not a practice exam. This is a module quiz from FLVS and it's cheating if you use this answer. Plus it has a obvious mistake in it. Mr. Carlyle
FLVS Chemistry Instructor
This question is a violation of the OpenStudy Guidelines. The question is from an online school plus a violation by solicitation for members to unknowingly assist them cheating on an exam. 30653065chem30653065
lmao ive seen that same message everywhere. Don't believe the "it has an obvious mistake" its bs