• anonymous
How many grams of zinc metal will react completely with 5.4 liters of 2.8 M HCl? Show all of the work needed to solve this problem. Zn (s) + 2 HCl (aq) -> ZnCl2 (aq) + H2 (g)
  • Stacey Warren - Expert
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  • chestercat
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  • Rogue
mol = molarity x volume n = MV 5.4 L * 2.8 M HCl = 15.12 mol HCl According to the balanced reaction, for every 2 moles of HCl, you need 1 mole of Zn to react. So for 15.12 mol HCl, you need 15.12/2 = 7.56 mol Zn. Now the molar mass of 65.4 g/mol. So in 7.56 mol Zn, there are 7.56 mol * 65.4 g/mol = 494. g Zn. So you need 494 grams of zinc to react completely with 5.4 liters of 2.8 M HCl.
  • anonymous
No.. This is not a practice exam. This is a module quiz from FLVS and it's cheating if you use this answer. Plus it has a obvious mistake in it. Mr. Carlyle FLVS Chemistry Instructor This question is a violation of the OpenStudy Guidelines. The question is from an online school plus a violation by solicitation for members to unknowingly assist them cheating on an exam. 30653065chem30653065
  • Baseballguy101
lmao ive seen that same message everywhere. Don't believe the "it has an obvious mistake" its bs

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