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jlovexx Group Title

How many grams of zinc metal will react completely with 5.4 liters of 2.8 M HCl? Show all of the work needed to solve this problem. Zn (s) + 2 HCl (aq) -> ZnCl2 (aq) + H2 (g)

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    mol = molarity x volume n = MV 5.4 L * 2.8 M HCl = 15.12 mol HCl According to the balanced reaction, for every 2 moles of HCl, you need 1 mole of Zn to react. So for 15.12 mol HCl, you need 15.12/2 = 7.56 mol Zn. Now the molar mass of 65.4 g/mol. So in 7.56 mol Zn, there are 7.56 mol * 65.4 g/mol = 494. g Zn. So you need 494 grams of zinc to react completely with 5.4 liters of 2.8 M HCl.

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