Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

jlovexx

  • 4 years ago

How many grams of zinc metal will react completely with 5.4 liters of 2.8 M HCl? Show all of the work needed to solve this problem. Zn (s) + 2 HCl (aq) -> ZnCl2 (aq) + H2 (g)

  • This Question is Closed
  1. Rogue
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    mol = molarity x volume n = MV 5.4 L * 2.8 M HCl = 15.12 mol HCl According to the balanced reaction, for every 2 moles of HCl, you need 1 mole of Zn to react. So for 15.12 mol HCl, you need 15.12/2 = 7.56 mol Zn. Now the molar mass of 65.4 g/mol. So in 7.56 mol Zn, there are 7.56 mol * 65.4 g/mol = 494. g Zn. So you need 494 grams of zinc to react completely with 5.4 liters of 2.8 M HCl.

  2. carlyle
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    No.. This is not a practice exam. This is a module quiz from FLVS and it's cheating if you use this answer. Plus it has a obvious mistake in it. Mr. Carlyle FLVS Chemistry Instructor This question is a violation of the OpenStudy Guidelines. The question is from an online school plus a violation by solicitation for members to unknowingly assist them cheating on an exam. 30653065chem30653065

  3. Baseballguy101
    • 9 months ago
    Best Response
    You've already chosen the best response.
    Medals 0

    lmao ive seen that same message everywhere. Don't believe the "it has an obvious mistake" its bs

  4. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy