A community for students. Sign up today!
Here's the question you clicked on:
 0 viewing
 2 years ago
How many grams of zinc metal will react completely with 5.4 liters of 2.8 M HCl? Show all of the work needed to solve this problem.
Zn (s) + 2 HCl (aq) > ZnCl2 (aq) + H2 (g)
 2 years ago
How many grams of zinc metal will react completely with 5.4 liters of 2.8 M HCl? Show all of the work needed to solve this problem. Zn (s) + 2 HCl (aq) > ZnCl2 (aq) + H2 (g)

This Question is Closed

Rogue
 2 years ago
Best ResponseYou've already chosen the best response.0mol = molarity x volume n = MV 5.4 L * 2.8 M HCl = 15.12 mol HCl According to the balanced reaction, for every 2 moles of HCl, you need 1 mole of Zn to react. So for 15.12 mol HCl, you need 15.12/2 = 7.56 mol Zn. Now the molar mass of 65.4 g/mol. So in 7.56 mol Zn, there are 7.56 mol * 65.4 g/mol = 494. g Zn. So you need 494 grams of zinc to react completely with 5.4 liters of 2.8 M HCl.
Ask your own question
Ask a QuestionFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.