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nikki156789
 3 years ago
15. Calculate NL.
a. 30
b. 48
c. 64
d. 72
16. Calculate MN.
a. 37.5
b. 80
c. 90
d. 54
nikki156789
 3 years ago
15. Calculate NL. a. 30 b. 48 c. 64 d. 72 16. Calculate MN. a. 37.5 b. 80 c. 90 d. 54

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nikki156789
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1332477081850:dw

nikki156789
 3 years ago
Best ResponseYou've already chosen the best response.0how would i go about finding these lengths if i dont have the equation to do so?

SUROJ
 3 years ago
Best ResponseYou've already chosen the best response.1You should use the concept of Similar triangle......the sides of similar triangle are proportional

nikki156789
 3 years ago
Best ResponseYou've already chosen the best response.0okso since it has two similar sides where would i go from there?

SUROJ
 3 years ago
Best ResponseYou've already chosen the best response.1did you find all the three angles of two triangles are same

nikki156789
 3 years ago
Best ResponseYou've already chosen the best response.0besides the given ones and l

SUROJ
 3 years ago
Best ResponseYou've already chosen the best response.1one is given initially, the other one are vertically opposite angles and since sum of all angles of triangle are 180 degree, the third angle is also equal

nikki156789
 3 years ago
Best ResponseYou've already chosen the best response.0ok so can you help me find nl?

nikki156789
 3 years ago
Best ResponseYou've already chosen the best response.0im like super bad at math...as you can tell

nikki156789
 3 years ago
Best ResponseYou've already chosen the best response.0so its 24 divided by 9? or is it a fraction?

SUROJ
 3 years ago
Best ResponseYou've already chosen the best response.1No, its (24*24/9).....did you catch it?

nikki156789
 3 years ago
Best ResponseYou've already chosen the best response.0or do i cross multiply? oh wait i get it now

nikki156789
 3 years ago
Best ResponseYou've already chosen the best response.0ok so what do i do for 16?

SUROJ
 3 years ago
Best ResponseYou've already chosen the best response.1is there any 16 anywhere?

nikki156789
 3 years ago
Best ResponseYou've already chosen the best response.0yes it says calculate MN

Directrix
 3 years ago
Best ResponseYou've already chosen the best response.1First, establish that the two triangles are similar. < J is congruent to <N as marked. <KLJ is congruent to <NLM because vertical angles are congruent. Two pairs of congruent angles is ALL you need to prove triangles similar. A third pair is unnecessary because of the theorem: If two angles of one triangle are congruent to two angles of another triangle, the third pair of angles are also congruent. That is why the AA Triangle Similarity Postulate has ONLY two As in it. Second, establish the correspondence of vertices of the two similar triangles. I got Triangle JKL ~ Triangle NML because J<>N from the marked congruent angles and L <> L because of the congruent vertical angles. Those correspondences force K < >M. Lengths of corresponding sides of similar triangles are in proportion. Looking at the triangle correspondence Triangle JKL ~ Triangle NML, the extended proportion is as follows: JK/NM = KL/ML = JL/NL. That equation comes directly from the triangle correspondence. JK was first and second in the lineup for Triangle JKL so it corresponds to NM, first and second in the lineup for Triangle NML. Then, I chose second and third to second and third, and finally 3rd and lst to 3rd and lst. Notice that I have not looked at the given lengths of any triangle sides because without the information above, I would not know how to set up the equations. JK/NM = KL/ML = JL/NL My next step is to fill in the known values in this extended proportion. 30 / (NM) = 9 / 24 = 24 / NL Select two fractions where you know 3 of the four quantities. 30 / (NM) = 9 / 24 9 (MN) = 30* 24 MN = (30* 24) / 9 MN = 80 > Option B  9 / 24 = 24 / NL 9 (NL) = 24*24 NL = (24*24) / 9 NL = 64 > Option C Note: When you work triangle similarity problems, it is *critical* to get the correspondence of the vertices FIRST. That gives you the corresponding sides in a proportion through which you can find the sides you seek. Do check my work to ensure that I correctly read the side lengths.
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