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what is NL?
how would i go about finding these lengths if i dont have the equation to do so?
You should use the concept of Similar triangle......the sides of similar triangle are proportional
okso since it has two similar sides where would i go from there?
did you find all the three angles of two triangles are same
besides the given ones and l
one is given initially, the other one are vertically opposite angles and since sum of all angles of triangle are 180 degree, the third angle is also equal
ok so can you help me find nl?
im like super bad at math...as you can tell
so see (NL/24)=(24/9)
and you can find NL
so its 24 divided by 9? or is it a fraction?
No, its (24*24/9).....did you catch it?
or do i cross multiply? oh wait i get it now
yea you cross multiply
ok so what do i do for 16?
is there any 16 anywhere?
yes it says calculate MN
First, establish that the two triangles are similar. < J is congruent to
N from the marked congruent angles and L <--> L because of the congruent vertical angles. Those correspondences force K <-- >M.
Lengths of corresponding sides of similar triangles are in proportion.
Looking at the triangle correspondence Triangle JKL ~ Triangle NML, the extended proportion is as follows:
JK/NM = KL/ML = JL/NL.
That equation comes directly from the triangle correspondence. JK was first and second in the line-up for Triangle JKL so it corresponds to NM, first and second in the line-up for Triangle NML. Then, I chose second and third to second and third, and finally 3rd and lst to 3rd and lst.
Notice that I have not looked at the given lengths of any triangle sides because without the information above, I would not know how to set up the equations.
JK/NM = KL/ML = JL/NL
My next step is to fill in the known values in this extended proportion.
30 / (NM) = 9 / 24 = 24 / NL
Select two fractions where you know 3 of the four quantities.
30 / (NM) = 9 / 24
9 (MN) = 30* 24
MN = (30* 24) / 9
MN = 80 ---> Option B
9 / 24 = 24 / NL
9 (NL) = 24*24
NL = (24*24) / 9
NL = 64 --> Option C
Note: When you work triangle similarity problems, it is *critical* to get the correspondence of the vertices FIRST. That gives you the corresponding sides in a proportion through which you can find the sides you seek. Do check my work to ensure that I correctly read the side lengths.