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badreferences
 2 years ago
Best ResponseYou've already chosen the best response.0The answer to "�" is "yes".

nikki156789
 2 years ago
Best ResponseYou've already chosen the best response.0dw:1332482220944:dw

nikki156789
 2 years ago
Best ResponseYou've already chosen the best response.0and angle q is 90 degrees

SUROJ
 2 years ago
Best ResponseYou've already chosen the best response.2did you see triangles MRS and MLR are similar?

badreferences
 2 years ago
Best ResponseYou've already chosen the best response.0Every detail is important, yo.

nikki156789
 2 years ago
Best ResponseYou've already chosen the best response.0shush badreferences

SUROJ
 2 years ago
Best ResponseYou've already chosen the best response.2so, see the corresponding equal angles.......did you actually see?

nikki156789
 2 years ago
Best ResponseYou've already chosen the best response.0yes i see those... im not blind

badreferences
 2 years ago
Best ResponseYou've already chosen the best response.0Dang, nikki, SUROJ is tying to help you. I don't mind you being snarky at me, but those helping you might misinterpret it.

SUROJ
 2 years ago
Best ResponseYou've already chosen the best response.2then find the ratio of corresponding sides

nikki156789
 2 years ago
Best ResponseYou've already chosen the best response.0idk what that is... see i told you earlier!!!!

nikki156789
 2 years ago
Best ResponseYou've already chosen the best response.0i did all of what you've said so far

nikki156789
 2 years ago
Best ResponseYou've already chosen the best response.0but idk what the ratio of corresponding sides is and how to find it.

Directrix
 2 years ago
Best ResponseYou've already chosen the best response.0@nikkil56789 After you read the last post at http://openstudy.com/users/directrix#/updates/4f6bfc90e4b0772daa078624 , I will help you with this problem.

SUROJ
 2 years ago
Best ResponseYou've already chosen the best response.2(MQ/ML)=(MT/MR) that gives MT=9.6, so TQ=169.6=6.4

Directrix
 2 years ago
Best ResponseYou've already chosen the best response.0Is segment RS given to be parallel to segment LR? With the given information, there is no reason to assume that any triangles shown are similar.
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