anonymous
  • anonymous
Solve the radical equation √(x+4) +√(x-4)=4
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
I don't know where to begin...can I square everything? to get rid of the square roots, that is.
anonymous
  • anonymous
√(x+4)=4 -√(x-4) x+4=x-8√(x-4)+12 4=-8√(x-4)+12
anonymous
  • anonymous
think you can solve it from there

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anonymous
  • anonymous
I am confused....why did you do what you just did?
anonymous
  • anonymous
subtract √(x-4) from both sides
anonymous
  • anonymous
square both sides
anonymous
  • anonymous
simplify
anonymous
  • anonymous
I understand. but why did you have to subtract the √(x-4) from both sides? can't we just square everything and combine like terms, isolate x and that is our answer?
anonymous
  • anonymous
well, if you square both sides, you get 2x+√(x+4)√(x-4)=16, which looks a lot more complicated
anonymous
  • anonymous
I mean 2x+2√(x+4)√(x-4)=16
anonymous
  • anonymous
no...you would get: (√(x+4))^2 +(√(x-4))^2=(4)^2 x+4 +x-4=16 which is 2x=16 x=8
anonymous
  • anonymous
that is my logic anyway
anonymous
  • anonymous
no, you gotta square everything
anonymous
  • anonymous
but I did
anonymous
  • anonymous
(√(x+4) +√(x-4))^2=(4)^2
anonymous
  • anonymous
the square gets rid of the square rooots
anonymous
  • anonymous
(√(x+4) +√(x-4))(√(x+4) +√(x-4))=16
anonymous
  • anonymous
oh
anonymous
  • anonymous
(√(x+4) +√(x-4))(√(x+4) +√(x-4)) does not equal (√(x+4))^2 +(√(x-4))^2
anonymous
  • anonymous
that is irritating... -_- so either way, I am going to have to foil....?
anonymous
  • anonymous
yep
anonymous
  • anonymous
meh :( well, thanks for your help
anonymous
  • anonymous
np

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