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the formula of a square would just be: Area of A = a^2
A sqare of side a = 20 m would have area 400 square mm so if that is what you are doing, then, yes, you are correct.
It ask me to explain each variable in the formulas of a square, rectangle, and triangle.
In the square formula, A = a^2, the variable a represents the side of the square. A square has all sides the same length. Bring the other two formulas over here and we'll do them.
This is for a triangle: Area of B = ½b × h = ½ × 20m × 14m = 140m2
Triangle: Area = 1/2 b x h where b is a base of the triangle and h represents the length of the altitude drawn to that base. If b = 20 m and h = 14 m , the area of the triangle is 1/2 (20) (14) = 140 m^2. Leave this "B" off and write "Area of triangle" = Now, get the rectangle formula and bring it here.
The formula for perimeter of a rectangle is: P = 2L + 2W.
Was this supposed to be area of a rectangle? I may be mixed up. ------- P = 2L + 2W is the formula for the perimeter of a rectangle. L represents the length of the rectangle and W represents the width. Some people write the formula as A = L + W + L + W. That equals 2L + 2W for the perimeter of the rectangle.
Then, get the area of a rectangle formula, bring it over here, and we'll crank it out. Perimeter is the distance around the rectangular region but area is how much region (area) in included inside the rectangle.
After that, then this question. I think something is missing. A water fountain with a 4 ft. by 4 ft square base is placed on a square grassy park area that is x ft on a side. To determine the amount of grass seed needed for the lawn, find a polynomial for the grassy area.
Would this be it Area=10.0x5.0=50.0
It might be an example but where is the formula for the area of a rectangle.A = ?
let me see
Area = w × h w = width h = height
|dw:1332488805458:dw| Fountain base area is A = s^2 = 4^2 = 16 Grass Plot area is A = s^2 = x^2 Region in park but not covered by fountain" Y = x^2 - 16
Area of a rectangle = w × h --This is correct but let's use L x W for length times width. Area of a rectangle = L x W where L represents the lengthh of the rectangle and W represents the width of the rectangle. If L = 10 m and W = 5 m, then Area=10.0x5.0=50.0 mm ^2
Did you see my interpretation of the water fountain problem?
Thank you! Very helpful:)
You should read the instructions and see if that's the way the picture is supposed to look. I don't know - I wrote that for you to check.
Nothing at this time.
What about this: 3. What is the effect on the area if each side is increased by same number? Be sure to show using an example what you say is true.
I need #3
Area of a rectangle = L x W where L represents the lengthh of the rectangle and W represents the width of the rectangle. If L = 10 m and W = 5 m, then Area=10.0x5.0=50.0 mm ^2 If L and W are increased by the same amount, then the new L is (10 +10 and the new W is (5 +5). The new area is -----? you find the new area and then we'll compare it to the old area. Post the new area (and the formula) here.
I'm clueless on this one.
Take a rectangle and crank out its area. You did that early on. Area of a rectangle = L x W where L represents the lengthh of the rectangle and W represents the width of the rectangle. If L = 10 m and W = 5 m, then Area=10.0x5.0=50.0 mm ^2 Now, the question said to increase the side lengths by the same amount. I'm taking that to mean double it, add 5 to 5 is the same as doubling 5. ----------------- Here's what you do: A = L * W A = 20 *10 and crank out that area and post here.
And, the answer is ? A = 20 *10 = ?
So, the area of the rectangle before doubling the sides was 50 square mm. Doubling the sides and finding the area gives 200 square mm. The original area of 50 was multiplied by 4 [ 50 * 4] = 200. The rule demonstrated is that if both sides of a rectangle are doubled, then the area is quadrupled (multiplied by 4). This also is true for the area of any figure with a formula with two variables that have both been doubled. So, if you have a triangle with area of 140 sq mm and you double the base and height of this triangle, then you know in advance that the area will be FOUR times 140 sq mm.
Glad to help. I knew you could do it.