anonymous
  • anonymous
Find the gradient of the normal to the curve, at the specified value of t. \[ (b)~~~ x=\cos^2t~~~~~~~ y=\sin^2t~~~~~~when~~ t = {1\over3}\pi\]
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
x' = -2costsint?
dumbcow
  • dumbcow
i think its asking for the same thing? gradient is dy/dx ?
anonymous
  • anonymous
Yes, but I have trig problems :/

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dumbcow
  • dumbcow
x' is right
anonymous
  • anonymous
Ok y'= 2sintcost?
dumbcow
  • dumbcow
yep
anonymous
  • anonymous
Ok, now how do I place in the value of x so that -2costsint --------- = something? 2sintcost
anonymous
  • anonymous
Would it be -1?
dumbcow
  • dumbcow
yeah looks like it all cancels dy/dx = -1
anonymous
  • anonymous
So, it would be m(-1)=-1
dumbcow
  • dumbcow
also note sin^2 +cos^2 = 1 --> x+y = 1 y = 1-x this has slope of -1
anonymous
  • anonymous
Ok, true. Well, since it's at the normal, the answer would be 1?
dumbcow
  • dumbcow
what is m?
anonymous
  • anonymous
m=slope
dumbcow
  • dumbcow
yes the normal is perpendicular
anonymous
  • anonymous
Great, thank you!
anonymous
  • anonymous
I might place another one up for reassurance.. and I show you what I do, and see if it's right?
dumbcow
  • dumbcow
ok
anonymous
  • anonymous
I placed it up

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